1 Škola: Gymnázium, Brno, Slovanské náměstí 7 Šablona: III/2 – Inovace a zkvalitnění výuky prostřednictvím ICT Název projektu: Inovace výuky na GSN prostřednictvím ICT Číslo projektu: CZ.1.07/1.5.00/ Autor: RNDr. Bc. Miroslav Hruška Tematická oblast: Kinematics of a particle (kinematika hmotného bodu) Název DUMu: Uniform motion – B Kód: VY_32_INOVACE_FY.2.08 Datum: Cílová skupina: Žáci středních škol s CLIL výukou fyziky v angličtině Klíčová slova:Uniform motion Anotace: Prezentace slouží k procvičení a rozšíření učiva z učebního materiálu Uniform motion – A, který se týká rovnoměrného pohybu.

Kinematics of a particle 8. Uniform motion – B

3 1. At uniform motion distance is constant 2. At uniform motion speed is equal to velocity 3. According to Czech textbooks of physics uniform motion can be only rectilinear 4. At uniform motion the graph of speed as a function of time is a line perpendicular to the axis t True or false?

Zdroj: archiv autora4  horse on a merry-go-round (na kolotoči)  suitcase on a baggage carousel  bee in the meadow  car in the city  volleyball player  Moon  parachutist (?) Decide what moves uniformly

5 Exercise I  At a quarter past eight a motorbike left LA at a speed of 80 km/h. At a quarter to nine a driver of a car set off at a speed of 90 km/h to catch the biker up. At what time did the car overtake the bike? Suppose the motions are uniform.  t 1 = 8:15, v 1 = 80 km/h  t 2 = 8:45, v 2 = 90 km/h

6 Solution I  At 8:45 the handicap of the car is s = v 1 Δt = 40 km  The car is approaching to the motorbike at a speed of 10 km/h relative to the bike  Time to cover 40 km at 10 km/h is Bike will be overtaken at 12:45! (360 km from LA)

7 Exercise II  A truck starts from A to B at 60 km/h. At the same moment a bus starts from B to A at 90 km/h. Distance from A to B is 100 km. What time will they meet in? Solution II  The bus is approching to the truck at 150 km/h! Time to cover 100 km is t = 100 km ÷ 150 km/h = 2/3 h = 40 min. The cars will meet in 40 minutes.

8 Exercise III  At 11 a.m. a motorbike left A at a speed of 70 km/h. At 1 p.m. a car set off at 120 km/h to catch the biker up. At what time did he succeed? Exercise IV  A tractor going at 10 m.s -1 and a car going at 20 m.s -1 are at a distance of 15 km aiming to each other. What distance will the tractor cover before they meet?

9 Distance as a function of time Find the formula of distance as a function of time according to the graph

10 Distance as a function of time Find the formula of distance as a function of time according to the graph

11 mechanics, kinematics, dynamics, motion, rest, frame of reference, relativity, particle, position, coordinate system, trajectory, rectilinear motion, curvilinear motion, distance, average speed, instantaneous speed, velocity, scalar, vector, magnitude, tangent, SI, base units, derived units, multiples, function, uniform motion Describe the terms you’ve learned

That is all for now Thank you for your attention

13  Materiál je určen pro bezplatné používání pro potřeby výuky a vzdělávání na všech typech škol a školských zařízeních. Jakékoliv další využití podléhá autorskému zákonu. Zdroje:  Bednařík, M., Široká, M. Fyzika pro gymnázia, Mechanika. Dotisk 3. vyd. Praha: Prometheus, s. ISBN  Hornby, A. S. Oxford Advanced Learner’s Dictionary of Current English. 5. vyd. Oxford: Oxford University Press, s. ISBN Autor nezaručuje funkčnost webových odkazů!